Let pi be a projective plane of order 15 with an oval Omega. Assume pi admits a collineation group G fixing Omega such that G is isomorphic to A(4) and the action of G on Omega yields precisely two orbits Omega(1) and Omega(2) with \Omega(2)\ = 4. We prove that the Buekenhout oval arising from Omega cannot exist.
On the non-existence of a projective plane of order 15 with an A 4-invariant oval / Aguglia, A.; Bonisoli, A.. - In: DISCRETE MATHEMATICS. - ISSN 0012-365X. - STAMPA. - 288:1-3(2004), pp. 1-7. [10.1016/j.disc.2004.06.018]
On the non-existence of a projective plane of order 15 with an A 4-invariant oval
Aguglia, A.;
2004-01-01
Abstract
Let pi be a projective plane of order 15 with an oval Omega. Assume pi admits a collineation group G fixing Omega such that G is isomorphic to A(4) and the action of G on Omega yields precisely two orbits Omega(1) and Omega(2) with \Omega(2)\ = 4. We prove that the Buekenhout oval arising from Omega cannot exist.File in questo prodotto:
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